(x+2)^2-3(x+2)-40=0

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Solution for (x+2)^2-3(x+2)-40=0 equation: 



(x+2)^2-3(x+2)-40=0

We multiply parentheses

(x+2)^2-3x-6-40=0

We add all the numbers together, and all the variables

-3x+(x+2)^2-46=0

We move all terms containing x to the left, all other terms to the right

-3x+(x+2)^2=46

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